Use C++-style declarator layout

Reason

The C-style layout emphasizes use in expressions and grammar, whereas the C++-style emphasizes types. The use in expressions argument doesn't hold for references.

Example

T& operator[](size_t);   // OK
T &operator[](size_t);   // just strange
T & operator[](size_t);   // undecided

Note

This is a recommendation for when you have no constraints or better ideas. This rule was added after many requests for guidance.

Enforcement

Impossible in the face of history.